What is the expected order of reactivity of t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reactivity of benzene derivatives towards electrophilic aromatic substitution depends on the nature of the substituent attached to the ring.$I

Vedclass · Accepted Answer

$II > III > I > IV$

Vedclass · Answer

(D) The reactivity of benzene derivatives towards electrophilic aromatic substitution depends on the nature of the substituent attached to the ring.$II$: $-N(CH_3)_2$ is a strongly activating group due to the $+M$ effect of the lone pair on nitrogen.$III$: $-OCOCH_3$ is a moderately activating group due to the $+M$ effect of the oxygen atom,though it is less activating than $-N(CH_3)_2$.$I$: $-CH_2CO_2H$ is a deactivating group because the $-CH_2-$ group is attached to an electron-withdrawing carboxylic acid group,exerting an $-I$ effect.$IV$: $-CCl_3$ is a strongly deactivating group due to the strong $-I$ effect of the three chlorine atoms.Therefore,the order of reactivity is $II > III > I > IV$.

What is the expected order of reactivity of the following compounds in electrophilic chlorination $(Cl_2 + FeCl_3)$? (more reactive $ > $ less reactive)
$I: C_6H_5CH_2CO_2H$
$II: C_6H_5N(CH_3)_2$
$III: C_6H_5OCOCH_3$
$IV: C_6H_5CCl_3$

Similar Questions

Catalytic oxidation of benzene at $500\,^oC$ in the presence of $V_2O_5$ gives ..........

Benzene is obtained by

Identify the product $(P)$ formed from the following reaction.

Which position will be attacked most rapidly by the nitronium ion $(NO_2)^+$ when the compound undergoes nitration with $HNO_3 / H_2SO_4$?

In the following set of aromatic compounds,the correct order of reactivity toward Friedel-Crafts alkylation is:
$(i)$ Nitrobenzene
(ii) Benzene
(iii) Methyl benzoate
(iv) Anisole

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the expected order of reactivity of the following compounds in electrophilic chlorination $(Cl_2 + FeCl_3)$? (more reactive $ > $ less reactive)$I: C_6H_5CH_2CO_2H$$II: C_6H_5N(CH_3)_2$$III: C_6H_5OCOCH_3$$IV: C_6H_5CCl_3$